Nilai dari operasi hitung (pxq) +r, jika p =4/3,q=2/3,r=2/3 adalah
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Jawaban:
~Pecahan
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Diket :
p = [tex] \frac{4}{3} [/tex]
q = [tex] \frac{2}{3} [/tex]
r = [tex] \frac{2}{3} [/tex]
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Ditanya :
Nilai dari (p × q) + r
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[tex]( \frac{4}{3} \: \times \: \frac{2}{3}) \: + \: \frac{2}{3} [/tex]
[tex] = \: \frac{4 \: \times \: 2}{3 \: \times \: 3} \: + \: \frac{2}{3} [/tex]
[tex] = \: \frac{8}{9} \: + \: \frac{2}{3} [/tex]
[tex] = \: \frac{8}{9} \: + \: \frac{6}{9} [/tex]
[tex]\sf = \frac{8 \: + \: 6}{9}[/tex]
[tex] = \: \frac{14}{9} [/tex]
[tex]{\blue{\boxed{\red{ = \: 1 \frac{5}{9} \: ✔ }}}}[/tex]
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